Question 1 [1 mark]
x = -5 ± √9
Mark scheme
- A [1] — cao x = -5 ± √9
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x = -5 ± √9
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x = 3 or x = -7
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(x - 3.5)² - 2.25
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2(x + 2)² - 2
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3(x - 2)² - 2
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(x + 0.75)² - 2.5625
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(3, 2)
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(x + 3)² - 1
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(x - 2)² - 3
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(x - 4)² - 9
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(x + 1)² - 6
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(x + 5)²
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(x + 2.5)² - 0.25
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(x + 0.5)² - 6.25
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x = 2.5 ± √3.25
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k ≤ 4
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8
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(-2, -3)
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x = [-b ± √b² - 4ac]/(2a)
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4(x + 3)² - 1
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x = -1 or x = -5
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x = 5 or x = -3
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x = 0.67 or x = -3.00
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x = 2 or x = 6
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x = 2 ± √2.25
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p = -4, q = -1
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2(x + 0.75)² - 5.125
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x = -3 or x = -4
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x = -1 or x = -5
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6(x - 1)² + 1
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